Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) — Push element x onto stack.
- pop() — Removes the element on top of the stack.
- top() — Get the top element.
- getMin() — Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); --> Returns -3. minStack.pop(); minStack.top(); --> Returns 0. minStack.getMin(); --> Returns -2.
Python
class MinStack(object): def __init__(self): """ initialize your data structure here. """ self.min_stack = [] self.min_num_stack = [] def push(self, x): """ :type x: int :rtype: void """ if len(self.min_num_stack) == 0 or x <= self.min_num_stack[-1]: self.min_num_stack.append(x) self.min_stack.insert(0, x) def pop(self): """ :rtype: void """ if self.min_stack[0] == self.min_num_stack[-1]: self.min_num_stack.pop() del self.min_stack[0] def top(self): """ :rtype: int """ return self.min_stack[0] def getMin(self): """ :rtype: int """ return self.min_num_stack[-1]