Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1] Output: 1
Example 2:
Input: [4,1,2,1,2] Output: 4
Python
class Solution(object): def singleNumber(self, nums): """ :type nums: List[int] :rtype: int """ return -(sum(nums) - 2 * sum(set(nums)))